9x^2=3-9x

Solution for 9x^2=3-9x equation:

9x^2=3-9x

We move all terms to the left:

9x^2-(3-9x)=0

We add all the numbers together, and all the variables

9x^2-(-9x+3)=0

We get rid of parentheses

9x^2+9x-3=0

a = 9; b = 9; c = -3;
Δ = b2-4ac
Δ = 92-4·9·(-3)
Δ = 189
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{189}=\sqrt{9*21}=\sqrt{9}*\sqrt{21}=3\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3\sqrt{21}}{2*9}=\frac{-9-3\sqrt{21}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3\sqrt{21}}{2*9}=\frac{-9+3\sqrt{21}}{18}
$